`( 3/4 . x - 1/2) . ( 0,25 . x + 4/3) = 0`
⇒ `+)` Trường hợp `1` :
`3/4 . x - 1/2 = 0`
`3/4 . x = 0 + 1/2`
`3/4 . x = 1/2`
`x = 1/2 : 3/4`
`x= 2/3`
`+)` Trường hợp `2` :
`0,25 . x + 4/3 = 0`
`1/4 . x + 4/3 = 0`
`1/4 . x = 0 - 4/3`
`1/4 . x = -4/3`
`x = -4/3 : 1/4`
`x= -16/3`
Vậy `x ∈ { 2/3 ; -16/3}`