Đáp án:
\(\left[ \begin{array}{l}x=0\\x= \frac{9}{2} \end{array} \right.\)
Giải thích các bước giải:
$\frac{x}{x-3}$ -$\frac{x}{x-5}$= $\frac{x}{x-4}$ -$\frac{x}{x-6}$
⇔x($\frac{1}{x-3}$ -$\frac{1}{x-5}$ -$\frac{1}{x-4}$ +$\frac{1}{x-6}$) =0
⇔\(\left[ \begin{array}{l}x=0\\\frac{1}{x-3} -\frac{1}{x-5} -\frac{1}{x-4} +\frac{1}{x-6}=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=0\\x= \frac{9}{2} \end{array} \right.\)
