Đáp án đúng: A
Giải chi tiết:\(\left\{ \begin{gathered} (2{p_M} + {n_M}) + (2{p_X} + {n_X}) = 84\,\,\,\,\,\,\,\,\,\,\,\,\,(1) \hfill \\ (2{p_M} + 2{p_X}) - (2{n_M} + {n_X}) = 28\,\,\,\,\,\,\,\,\,\,\,(2) \hfill \\ {n_M} - {n_X} = 12\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(3) \hfill \\ (2{p_M} + {n_M}) - (2{p_X} + {n_X}) = 36\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(4) \hfill \\ \end{gathered} \right.\)
Lấy (1)+(2) => 4pM+ 4pX= 112 => pM +pX = 28
Lấy 4)-(3) => 2pM- 2pX = 24 => pM-pX = 12
\(\left\{ \begin{gathered} {p_{M\;}} + {p_X} = {\text{ }}28 \hfill \\ {p_{M\;}} - {p_X} = {\text{ 12}} \hfill \\ \end{gathered} \right. \to \left\{ \begin{gathered} {p_M} = 20 \hfill \\ {p_X} = 8 \hfill \\ \end{gathered} \right.\)
=> MX: CaO
Đáp án A