Tìm x:
a) \(x - \frac{1}{2} = \frac{3}{2}\)
b) \(\left| {x + \frac{3}{4}} \right| - \frac{1}{2} = \sqrt {\frac{9}{4}} \)
c) \(4\frac{2}{3}.x - {\left( {\frac{{ - 2}}{3}} \right)^2} = {\left( {2,3 - 5,7} \right)^0}\)
A.\(a)x = 2;\,\,b)\,\left[ \begin{array}{l}x = \frac{5}{4}\\x = \frac{{ - 11}}{4}\end{array} \right.;\,\,\,c)\,x = \frac{{15}}{{43}}\,\)
B.\(a)x = 2;\,\,b)\,\left[ \begin{array}{l}x = \frac{5}{4}\\x = \frac{{ - 11}}{4}\end{array} \right.;\,\,\,c)\,x = \frac{{13}}{{43}}\,\)
C.\(a)x = 3;\,\,b)\,\left[ \begin{array}{l}x = \frac{5}{4}\\x = \frac{{ - 11}}{4}\end{array} \right.;\,\,\,c)\,x = \frac{{13}}{{43}}\,\)
D.\(a)x = 2;\,\,b)\,\left[ \begin{array}{l}x = \frac{7}{4}\\x = \frac{{ - 11}}{4}\end{array} \right.;\,\,\,c)\,x = \frac{{13}}{{43}}\,\)
