Quy luật dãy số \(B=\left(\dfrac{1}{1+2}-1\right)+\left(\dfrac{1}{1+2+3}-1\right)+\left(\dfrac{1}{1+2+3+4}-1\right)+...+\left(\dfrac{1}{1+2+..+9}-1\right)\)\(B=\left(\dfrac{1}{1+2}\right)+\left(\dfrac{1}{1+2+3}\right)+\left(\dfrac{1}{1+2+3+4}\right)+...+\left(\dfrac{1}{1+2+..+9}\right)-8\)\(B=B_1-8\)