Giải hệ phương trình \( \left \{ \begin{array}{l}2{x^3} + 2{x^2}y - xy = {y^2} - x - y \ \2{x^3} - xy + {x^2} = 4 \end{array} \right. \)
A.\(\left( {x;y} \right) \in \left\{ {\left( {\dfrac{{1 - \sqrt {15} }}{2};10 + \sqrt {15} } \right)} \right\}\).
B.\(\left( {x;y} \right) \in \left\{ {\left( {\dfrac{{-1 - \sqrt {17} }}{2};10 - \sqrt {17} } \right);\left( {1; - 1} \right)} \right\}\).
C.\(\left( {x;y} \right) \in \left\{ {\left( {1; - 1} \right)} \right\}\).
D.\(\left( {x;y} \right) \in \left\{ {\left( {\dfrac{{-1 - \sqrt {17} }}{2};10 + \sqrt {17} } \right)} \right\}\).
A.\(\left( {x;y} \right) \in \left\{ {\left( {\dfrac{{1 - \sqrt {15} }}{2};10 + \sqrt {15} } \right)} \right\}\).
B.\(\left( {x;y} \right) \in \left\{ {\left( {\dfrac{{-1 - \sqrt {17} }}{2};10 - \sqrt {17} } \right);\left( {1; - 1} \right)} \right\}\).
C.\(\left( {x;y} \right) \in \left\{ {\left( {1; - 1} \right)} \right\}\).
D.\(\left( {x;y} \right) \in \left\{ {\left( {\dfrac{{-1 - \sqrt {17} }}{2};10 + \sqrt {17} } \right)} \right\}\).
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Hóa Học lớp 12
