Đáp án đúng: C
Giải chi tiết:\(\begin{array}{l}{n_{glucozo}} = 0,12\,mol\\1\,Sac \to 1\,Glu\, + \,1\,Fruc\\0,12\,\, \leftarrow \,\,0,12\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(mol)\\H = 80\% \Rightarrow m = {m_{sacc{\rm{orozo}}\,{\rm{(thuc}}\,{\rm{te}}\,{\rm{da}}\,{\rm{dung)}}}} = \frac{{100}}{{80}}.0,12.342 = 51,3\,gam.\end{array}\)
Đáp án C