Cho \(\frac{a}{b}=\frac{c}{d}\) . Chứng minh rằng:
a) \(\frac{3a+2c}{3b+2d}=\frac{-5a+3c}{-5b+3b}\) b) \(\frac{ac}{bd}=\frac{{{a}^{2}}+{{c}^{2}}}{{{b}^{2}}+{{d}^{2}}}\)
A.
B.
C.
D.
a) \(\frac{3a+2c}{3b+2d}=\frac{-5a+3c}{-5b+3b}\) b) \(\frac{ac}{bd}=\frac{{{a}^{2}}+{{c}^{2}}}{{{b}^{2}}+{{d}^{2}}}\)
A.
B.
C.
D.
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