Đáp án:
a, \(\left\{ \begin{array}{l}
x = 1\\
y = - 1
\end{array} \right.\)
b, \(\left\{ \begin{array}{l}
x = \frac{{31}}{4}\\
y = \frac{3}{2}
\end{array} \right.\)
Giải thích các bước giải:
\(\begin{array}{l}
a,\left\{ \begin{array}{l}
2(x - 2) + 3(y + 1) = - 2\\
3(x - 2) - 2(y + 1) = - 3
\end{array} \right.\\
\Leftrightarrow \left\{ \begin{array}{l}
6(x - 2) + 9(y + 1) = - 6\\
6(x - 2) - 4(y + 1) = - 6
\end{array} \right.\\
\Leftrightarrow \left\{ \begin{array}{l}
6(x - 2) + 9(y + 1) = - 6\\
13(y + 1) = 0
\end{array} \right.\\
\Leftrightarrow \left\{ \begin{array}{l}
6(x - 2) + 9(y + 1) = - 6\\
y = - 1
\end{array} \right.\\
\Leftrightarrow \left\{ \begin{array}{l}
x = 1\\
y = - 1
\end{array} \right.\\
b,\left\{ \begin{array}{l}
2x - 3y = 11\\
- 4 + 6y = 5
\end{array} \right.\\
\Leftrightarrow \left\{ \begin{array}{l}
2x - 3y = 11\\
y = \frac{3}{2}
\end{array} \right.\\
\Leftrightarrow \left\{ \begin{array}{l}
x = \frac{{31}}{4}\\
y = \frac{3}{2}
\end{array} \right.
\end{array}\)
