Giải thích các bước giải:
$\dfrac{5x+2}{x^2-10x}+\dfrac{5x-2}{x^2+10x}$
$=\dfrac{5x+2}{x(x-10)}+\dfrac{5x-2}{x(x+10)}$
$=\dfrac{(5x+2)(x+10)}{x(x-10)(x+10)}+\dfrac{(5x-2)(x-10)}{x(x+10)(x-10)}$
$=\dfrac{(5x+2)(x+10)+(5x-2)(x-10)}{x(x+10)(x-10)}$
$=\dfrac{10x^2+40}{x(x+10)(x-10)}$