Đáp án:
$(x-5)(2x-4)=0$
$⇔$\(\left[ \begin{array}{l}x-5=0\\2x-4=0\end{array} \right.\)
$⇔$\(\left[ \begin{array}{l}x=5\\x=2\end{array} \right.\)
Vậy $\text{x ∈ {5 ; 2}}$
$[(x^2+54) -32]2 =244$
$⇔(x^2+54) -32 = 244 : 2$
$⇔(x^2+54 ) - 32 = 122$
$⇔x^2+54 = 122 +32$
$⇔x^2+54 = 154$
$⇔x^2 =154 - 54$
$⇔x^2=100$
$⇔x = ± 10$
Vậy $x=±10$