\(5^{x^2+x-6}=1\)
\(\Rightarrow5^{x^2+x-6}=5^0\)
Vì \(5e-1;5e0;5e1\) nên
\(x^2+x-6=0\)
\(\Rightarrow x^2-2x+3x-6=0\)
\(\Rightarrow x.\left(x-2\right)+3.\left(x-2\right)=0\)
\(\Rightarrow\left(x-2\right).\left(x+3\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x-2=0\\x+3=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=2\\x=-3\end{matrix}\right.\)
Vậy--...
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