`( x + 5/6 ) . 2 2/5 - 1 1/4 = 35%`
`⇔ ( x + 5/6 ) . 12/5 - 5/4 = 7/20`
`⇔ ( x + 5/6 ) . 12/5 = 7/20 + 5/4`
`⇔ ( x + 5/6 ) . 12/5 = 8/5`
`⇔ x + 5/6 = 8/5 : 12/5`
`⇔ x + 5/6 = 2/3`
`⇔ x = 2/3 - 5/6`
`⇔ x = ( - 1 )/6`
Vậy `, x = ( - 1 )/6 .`
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`| x - 1 | - 12/16 = 25%`
`⇔ | x - 1 | - 3/4 = 1/4`
`⇔ | x - 1 | = 1/4 + 3/4`
`⇔ | x - 1 | = 1`
`⇔` $\left[\begin{matrix}x - 1 = 1\\x - 1 = - 1\end{matrix}\right.$
`⇔` $\left[\begin{matrix}x = 2\\x = 0\end{matrix}\right.$
Vậy `, x ∈ { 2 ; 0 } .`
