Đk x khác -1
\(\frac{2x+m-1}{x+1}>0\)(1)
TH(I) \(\frac{m-1}{2}=-1\Rightarrow m=-1\) \(\left(1\right)\Leftrightarrow\frac{2\left(x-1\right)}{x+1}=2\forall xe-1\)
TH(II) \(\frac{\left(m-1\right)}{2}>-1\Rightarrow m>-1\)(1) có nghiệm \(\left[\begin{matrix}x< -1\\x>\frac{m-1}{2}\end{matrix}\right.\)
TH(III) \(\frac{\left(m-1\right)}{2}< -1\Rightarrow m< -1\)(1) có nghiệm \(\left[\begin{matrix}x< \frac{\left(m-1\right)}{2}\\x>-1\end{matrix}\right.\)
Kết luận nghiệm.
\(\left[\begin{matrix}\left\{\begin{matrix}m=-1\\N_o\forall xe-1\end{matrix}\right.\\\left\{\begin{matrix}m>-1\\\left[\begin{matrix}x>\frac{m-1}{2}\\x< -1\end{matrix}\right.\end{matrix}\right.\\\left\{\begin{matrix}m< -1\\\left[\begin{matrix}x< \frac{m-1}{2}\\x>-1\end{matrix}\right.\end{matrix}\right.\end{matrix}\right.\)