Đáp án:
Ca(OH)2
MCa(OH)2 = 40+16.2+1.2 = 74 đvC
%Ca = $\frac{40}{74}$ . 100 = 54,05%
%O = $\frac{32}{74}$ . 100 = 43,24%
%H = 100 - 54,05 - 43,24 = 2,71%
CaCO3
MCaCO3 = 40+12+16.3 = 100 đvC
%Ca = $\frac{40}{100}$ . 100 = 40%
%C = $\frac{12}{100}$ . 100 = 12%
%O = 100 - 40 - 12 = 48%