Đáp án:
B
Giải thích các bước giải:
\(\begin{array}{l}
\sin \dfrac{a}{3} = \dfrac{3}{5} \Rightarrow {\sin ^2}\dfrac{a}{3} = \dfrac{9}{{25}}\\
\Rightarrow {\cos ^2}\frac{a}{3} = 1 - {\sin ^2}\dfrac{a}{3} = 1 - \dfrac{9}{{25}} = \dfrac{{16}}{{25}}\\
\Rightarrow P = 3{\sin ^2}\dfrac{a}{3} + 5{\cos ^2}\dfrac{a}{3}\\
\,\,\,\,\,\,\,\,\,\,\,\, = 3.\dfrac{9}{{25}} + 5.\dfrac{{16}}{{25}} = \dfrac{{107}}{{25}}
\end{array}\)