Đáp án:
-1
Giải thích các bước giải:
\[\begin{array}{l}
P = \frac{{2bc - 2016}}{{3c - 2bc + 2016}} - \frac{{2b}}{{3 - 2b + ab}} + \frac{{4032 - 3ac}}{{3ac - 4032 + 2016a}}\\
= \frac{{2bc - abc}}{{3c - 2bc + abc}} - \frac{{2b}}{{3 - 2b + ab}} + \frac{{2abc - 3ac}}{{3ac - 2abc + {a^2}bc}}\\ (do abc=2016)
= \frac{{c\left( {2b - ab} \right)}}{{c\left( {3 - 2b + ab} \right)}} - \frac{{2b}}{{3 - 2b + ab}} + \frac{{ac\left( {2b - 3} \right)}}{{ac\left( {3 - 2b + ab} \right)}}\\
= \frac{{2b - ab - 2b + 2b - 3}}{{3 - 2b + ab}}\\
= \frac{{ - \left( {3 - 2b + ab} \right)}}{{3 - 2b + ab}}\\
= - 1
\end{array}\]