Đáp án đúng: C
Giải chi tiết:\(\begin{gathered} {n_{{C_6}{H_{10}}{O_5}bd}} = \frac{m}{{162}} \hfill \\ {C_6}{H_{10}}{O_5}\xrightarrow{{ + {H_2}O,{H^ + },{t^o}}}{C_6}{H_{12}}{O_6}\xrightarrow{{ + AgN{O_3}/N{H_3}}}2Ag \hfill \\ \frac{m}{{216}}(mol)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \leftarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{m}{{108}} \hfill \\ \to H\% = \frac{{\frac{m}{{216}}}}{{\frac{m}{{162}}}}.100\% = 75\% \hfill \\ \end{gathered} \)
Đáp án C