Tích phân $I=\int\limits_{0}^{\frac{1}{\sqrt{3}}}{\frac{{{x}^{8}}}{{{({{x}^{4}}-1)}^{2}}}dx}$ bằng
A. $\frac{1}{\sqrt{3}}+\frac{1}{4}\ln \frac{\sqrt{3}-1}{\sqrt{3}+1}+\frac{\pi }{12}-1.$
B. $\frac{1}{\sqrt{3}}+\frac{1}{4}\ln \frac{\sqrt{3}-1}{\sqrt{3}+1}+\frac{\pi }{12}.$
C. $\frac{1}{\sqrt{3}}+\frac{1}{4}\ln \frac{\sqrt{3}-1}{\sqrt{3}+1}+\frac{\pi }{12}-12.$
D. $\frac{1}{\sqrt{3}}+\frac{1}{4}\ln \frac{\sqrt{3}-1}{\sqrt{3}+1}+\frac{\pi }{12}-2.$