Đáp án:
$\begin{array}{l}
\left| {{q_1}} \right| = {4.10^{ - 9}}\left( C \right)\\
\left| {{q_2}} \right| = {12.10^{ - 9}}\left( C \right)
\end{array}$
Giải thích các bước giải:
$\begin{array}{l}
{q_1} = - 3{q_2}\\
{F_{12}} = {F_{21}} = \frac{{k\left| {{q_1}{q_2}} \right|}}{{{r^2}}} = \frac{{{{9.10}^9}.\left( {3{q_2}^2} \right)}}{{0,{{06}^2}}} = 1,{2.10^{ - 4}}\\
\Rightarrow {q_2} = {4.10^{ - 9}}\left( C \right)\\
{q_1} = - {12.10^{ - 9}}\left( C \right)
\end{array}$
vậy $\begin{array}{l}
\left| {{q_1}} \right| = {4.10^{ - 9}}\left( C \right)\\
\left| {{q_2}} \right| = {12.10^{ - 9}}\left( C \right)
\end{array}$