1.\(\dfrac{5}{7}+\dfrac{2}{3}\cdot x=\dfrac{3}{10}\)
2.\(\left(x-\dfrac{1}{2}\right):\dfrac{1}{3}+\dfrac{5}{7}=9\dfrac{5}{7}\)
Loga
Toán lớp 7
1.\(\dfrac{5}{7}+\dfrac{2}{3}\cdot x=\dfrac{3}{10}\)
2.\(\left(x-\dfrac{1}{2}\right):\dfrac{1}{3}+\dfrac{5}{7}=9\dfrac{5}{7}\)
