Giải thích các bước giải:
c.Vì $\Diamond ABDC$ là hình chữ nhật
$\rightarrow AD=BC\rightarrow BE=AD=BC\rightarrow \widehat{BCE}=\widehat{BEC}=\widehat{ECN}(BM//CN)$
$\rightarrow \widehat{BCE}=\widehat{ECN}$
Do $CN\perp AD\rightarrow \widehat{NCD}=\widehat{ADB}(+\widehat{CND}=90^o)$
$\rightarrow \widehat{NCD}=\widehat{ADB}=\widehat{DAC}=\widehat{BCA}$
$\rightarrow\widehat{DCN}+\widehat{NCE}=\widehat{ACB}+\widehat{BCE}$
$\rightarrow\widehat{ACE}=\widehat{ECD}$
Mà $\widehat{ACE}+\widehat{ECD}=90^o$
$\rightarrow \widehat{ACE}=\widehat{ECD}=45^o$
$\rightarrow đpc$