Đáp án đúng: A
0,472M
$\left\{ \begin{array}{l}56{{n}_{Fe}}\,+\,232{{n}_{F{{e}_{3}}{{O}_{4}}}}\,=\,5,584\,gam\\3{{n}_{Fe}}\,+\,{{n}_{F{{e}_{3}}{{O}_{4}}}}\,=\,3{{n}_{NO}}\,=\,0,042\end{array} \right.\,\Rightarrow \,\left\{ \begin{array}{l}{{n}_{Fe}}\,=\,{{6,5.10}^{-3}}\\{{n}_{F{{e}_{3}}{{O}_{4}}}}\,=\,0,0225\end{array} \right.$
${{n}_{HN{{O}_{3}}}}\,=\,3{{n}_{Fe}}\,+\,9{{n}_{F{{e}_{3}}{{O}_{4}}}}\,+\,{{n}_{NO}}\,=\,0,236\,\Rightarrow \,{{C}_{M}}\,=\,0,472M$