a) ta có : \(\overrightarrow{AB}+\overrightarrow{CD}=\overrightarrow{AD}+\overrightarrow{DB}+\overrightarrow{CB}+\overrightarrow{BD}=\overrightarrow{AD}+\overrightarrow{CB}\left(đpcm\right)\)
b) ta có : \(\overrightarrow{AC}+\overrightarrow{BD}=\overrightarrow{AI}+\overrightarrow{IJ}+\overrightarrow{JC}+\overrightarrow{BI}+\overrightarrow{IJ}+\overrightarrow{JD}\)
ta có : \(\overrightarrow{AD}+\overrightarrow{BC}=\overrightarrow{AI}+\overrightarrow{IJ}+\overrightarrow{JD}+\overrightarrow{BI}+\overrightarrow{IJ}+\overrightarrow{JC}\)