Khi khai triển $\displaystyle P\left( x \right)={{\left( x-2y \right)}^{6}}$ thành đa thức thì
A. $\displaystyle P\left( x \right)={{x}^{6}}-6{{x}^{5}}y+15{{x}^{4}}{{y}^{2}}-20{{x}^{3}}{{y}^{3}}+15{{x}^{2}}{{y}^{4}}-6x{{y}^{5}}+{{y}^{6}}$
B. $\displaystyle P\left( x \right)={{x}^{6}}-6{{x}^{5}}2y+15{{x}^{4}}2{{y}^{2}}-20{{x}^{3}}2{{y}^{3}}+15{{x}^{2}}2{{y}^{4}}-6x2{{y}^{5}}++{{y}^{6}}$
C. $\displaystyle P\left( x \right)={{x}^{6}}+6{{x}^{5}}2y+15{{x}^{4}}2{{y}^{2}}+20{{x}^{3}}2{{y}^{3}}+15{{x}^{2}}2{{y}^{4}}-6x2{{y}^{5}}+2{{y}^{6}}$
D. $\displaystyle P\left( x \right)={{x}^{6}}-12{{x}^{5}}y+60{{x}^{4}}{{y}^{2}}-160{{x}^{3}}{{y}^{3}}+240{{x}^{2}}{{y}^{4}}-192x{{y}^{5}}+64{{y}^{6}}$
A. $\displaystyle P\left( x \right)={{x}^{6}}-6{{x}^{5}}y+15{{x}^{4}}{{y}^{2}}-20{{x}^{3}}{{y}^{3}}+15{{x}^{2}}{{y}^{4}}-6x{{y}^{5}}+{{y}^{6}}$
B. $\displaystyle P\left( x \right)={{x}^{6}}-6{{x}^{5}}2y+15{{x}^{4}}2{{y}^{2}}-20{{x}^{3}}2{{y}^{3}}+15{{x}^{2}}2{{y}^{4}}-6x2{{y}^{5}}++{{y}^{6}}$
C. $\displaystyle P\left( x \right)={{x}^{6}}+6{{x}^{5}}2y+15{{x}^{4}}2{{y}^{2}}+20{{x}^{3}}2{{y}^{3}}+15{{x}^{2}}2{{y}^{4}}-6x2{{y}^{5}}+2{{y}^{6}}$
D. $\displaystyle P\left( x \right)={{x}^{6}}-12{{x}^{5}}y+60{{x}^{4}}{{y}^{2}}-160{{x}^{3}}{{y}^{3}}+240{{x}^{2}}{{y}^{4}}-192x{{y}^{5}}+64{{y}^{6}}$
Loga
Hóa Học lớp 12
