Đáp án đúng: A
22,17
$\begin{array}{l}6Si{{O}_{2}}+CaC{{O}_{3}}+N{{a}_{2}}C{{O}_{3}}\to N{{a}_{2}}O.CaO.6Si{{O}_{2}}+2C{{O}_{2}}\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,106\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,478\,\,\,(g/mol)\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,100\,\,\,\,(kg)\\\Rightarrow {{m}_{N{{a}_{2}}C{{O}_{3}}}}=100.106/478=22,17(kg)\end{array}$