\(x\left(2x-3\right)-2\left(3x-2\right)=0\\ 2x^2-3x-6x+4=0\\ 2x^2-9x+4=0\\ x^2-\dfrac{9}{2}x+2=0\\ x^2-2.\dfrac{9}{4}+\left(\dfrac{9}{4}\right)^2=\left(\dfrac{9}{4}\right)^2-2\\ \left(x-\dfrac{9}{4}\right)^2=\dfrac{49}{16}\\ \Rightarrow\left[{}\begin{matrix}x-\dfrac{9}{4}=\dfrac{7}{4}\\x-\dfrac{9}{4}=-\dfrac{7}{4}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{16}{4}=4\\x=\dfrac{2}{4}=\dfrac{1}{2}\end{matrix}\right.\)
