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lechian298
2 năm trước
Cho tam giác ABC vuông tại A(AB<AC)có AH đường cao a)C/m:Tam giác HBA đồng dạng với tam giác ABC.SUy ra AB^2=BH.BC b)Phân giác góc ABC cắt AH,AC lần lượt tại E và I.C/M:tam giác BEA~tam giác BIC c)C/M:AI=AE và AI^2=EH.IC d)Đường thẳng qua C vuông góc BI tại N.C/m:góc BAN =góc AIN Giúp e câu d
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