Đáp án đúng: A Ta có: $ D=\underset{x\to -\infty }{\mathop{\lim }}\,\dfrac{\sqrt{{ x ^ 2 }+1}+2x+1}{\sqrt[3]{2{ x ^ 3 }+x+1}+x}$
$=\underset{x\to -\infty }{\mathop{\lim }}\,\dfrac{\left| x \right|\sqrt{1+\dfrac{1}{{}{ x ^ 2 }}}+2x+1}{x.\sqrt[3]{2+\dfrac{1}{{}{ x ^ 2 }}+\dfrac{1}{{}{ x ^ 3 }}}+x} $
$ =\underset{x\to -\infty }{\mathop{\lim }}\,\dfrac{-\sqrt{1+\dfrac{1}{{}{ x ^ 2 }}}+2+\dfrac{1}{x} }{\sqrt[3]{2+\dfrac{1}{{}{ x ^ 2 }}+\dfrac{1}{{}{ x ^ 3 }}}+1}=\dfrac{1}{{}\sqrt[3] 2 +1} $