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duongthuybmt47
2 năm trước
Cho 2 đường tròn (O) và (O') cắt nhau tại A, B. Vẽ dây AC của đường tròn (O) tiếp xúc với đường tròn (O'). Vẽ dây AD của đường tròn (O') tiếp xúc với đường tròn (O). CMR: a) BC . BD = BA^2 b) BC/BD = (AC / AD) ²
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