Tìm x, biết:
\(\left(4x-3\right)^2=\left(4x-3\right)\)
Giúp mik nha.
Chìu nay mik nộp rồi .
\(\left(4x-3\right)^2=4x-3\)
\(\Leftrightarrow\left(4x-3\right)^2-\left(4x-3\right)=0\)
\(\Leftrightarrow\left(4x-3\right)^2.\left[\left(4x-2\right)^2-1\right]=0\)
\(\Leftrightarrow\left[{}\begin{matrix}\left(4x-3\right)^2=0\\\left(4x-3\right)^2-1=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}\left(4x-3\right)^2=0^2\\\left(4x-3\right)^2=1^2\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}4x-3=0\\\left[{}\begin{matrix}4x-3=1\\4x-3=-1\end{matrix}\right.\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{4}\\\left[{}\begin{matrix}x=1\\x=\dfrac{1}{2}\end{matrix}\right.\end{matrix}\right.\)
Vậy ...
\(\dfrac{2^{15}.9^4}{6^6.8^3}\)
bài 1 cho B = \(\dfrac{1}{2}+\left(\dfrac{1}{2}\right)^2+...+\left(\dfrac{1}{2}\right)^{99}\)
CMR :
a) B <1
b) B ko là số nguyên
Tìm n \(\in\) N biết: \(3^n.2^n=216\)
1,Tìm x thuộc Q biết
a,\(\left(3x-1\right)^4=81\)
b,\(\left(x+1\right)^5=32\)
Chung minh rang
a,76+75-74\(⋮\)11
b,109+108+107\(⋮\)222
a) (0, 5)2
b) (0, 5)3
c) (9, 7)0
So sánh :
\(\dfrac{2^{2010}+1}{2^{2007}+1}\) và\(\dfrac{2^{2012}+1}{2^{2009}+1}\)
Tìm x,biết: a)x : \((\dfrac{3}{4})^{3} = (\dfrac{3}{4})^{2} \) b) \(\dfrac{2}{5}^{5} . x = \dfrac{2}{5}^{8}\)
Chứng minh rằng:
M = \(\dfrac{1}{3}+\dfrac{2}{3^2}+\dfrac{3}{3^3}+\dfrac{4}{3^4}+...+\dfrac{100}{3^{100}}\)<\(\dfrac{3}{4}\)
tìm giá trị của biểu thức sau
a) 45 mũ 10 . 5 mũ 20 / 75 mũ 15
b) (0,8) mũ 5 / (0,4) mũ 6
c) 2 mũ 15 . 9 mũ 4 / 6 mũ 6 . 8 mũ 3
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