Đáp án:
Al
Giải thích các bước giải:
\(\begin{array}{l}
mM + mC{l_2} = m\\
= > mC{l_2} = m - mM = 4,944a - a = 3,944g\\
nC{l_2} = \dfrac{{3,944a}}{{71}} = \dfrac{{493a}}{{8875}}\,mol\\
2M + nC{l_2} \to 2MC{l_n}\\
nM = \dfrac{{493a}}{{8875}} \times \dfrac{2}{n} = \dfrac{{986a}}{{8875n}}\,mol\\
MM = \dfrac{a}{{\dfrac{{986a}}{{8875n}}}} = 9n\,g/mol\\
n = 3 = > MM = 27g/mol\\
= > M:Al
\end{array}\)