Đáp án:
a/MnO2 + 4HCl đ $\buildrel{{t^o}}\over\longrightarrow$ MnCl2 + Cl2 + 2H2O
3Cl2 + 6KOHđ $\buildrel{{100^oC}}\over\longrightarrow$ KClO3 +5KCl +3H2O
2KClO3 $\buildrel{{t^o}}\over\longrightarrow$ 2KCl + 3O2
2KCl + 2H2O $\buildrel{{đpdd,cmn}}\over\longrightarrow$ 2KOH + Cl2 + H2
2KOH + Cl2 --> KClO + KCl + H2O
b/
NaOH + HCl --> NaCl + H2O
2NaCl $\buildrel{{đpnc}}\over\longrightarrow$ 2Na + Cl2
3Cl2 + 2Fe $\buildrel{{t^o}}\over\longrightarrow$ 2FeCl3
FeCl3 + 3NaOH --> Fe(OH)3 + 3NaCl
Fe(OH)3 + 3HCl--> FeCl3 + 3H2O
Giải thích các bước giải:
