Đáp án:
Giải thích các bước giải:
\(\begin{array}{l}
B1:\\
1.3x - 3 - 4 = 2x + 2 - 7\\
\to x = 1\\
2.{x^2} + 4x + 4 - 3x + 3 = {x^2} - x - 2\\
\to 2x = - 9\\
\to x = - \frac{9}{2}\\
B2:\\
1.\left[ \begin{array}{l}
3x - 2 = 0\\
4x + 5 = 0
\end{array} \right. \to \left[ \begin{array}{l}
x = \frac{2}{3}\\
x = \frac{{ - 5}}{4}
\end{array} \right.\\
2.\left( {2x - 3} \right)\left( {2x - 3 - x - 1} \right) = 0\\
\to \left[ \begin{array}{l}
2x - 3 = 0\\
x - 4 = 0
\end{array} \right. \to \left[ \begin{array}{l}
x = \frac{3}{2}\\
x = 4
\end{array} \right.
\end{array}\)
