$a$,$2x+12$=$3$.($x-7$)
⇔$2x + 12$=$3x - 21$
⇔$2x + 33$ =$3x$
⇔ $x=33$
Vậy $x=33$
$b$,$6a+1$ ⋮ $3a-1$
⇔$6a+1$ - $2$($3a-1$) ⋮ $3a-1$
⇔$6a +1 -6a +2$⋮ $3a-1$
⇔ $3 ⋮ 3a-1$
⇒$3a - 1$ ∈ Ư($3$)={$±1;±3$}
Mà $3a - 1$ chia $3$ dư $2$ hoặc $-1$
⇒$3a - 1 = -1$⇔$3a=0$⇔$a=0$
Vậy $a=0$