Cho tứ diện \(ABCD\). Gọi \(M\) là trung điểm \(AB\) và \(G\) là trọng tâm \(\Delta BCD\). Đặt \(\overrightarrow {AB} = \overrightarrow b ,\,\,\overrightarrow {AC} = \overrightarrow c ,\,\,\overrightarrow {AD} = \overrightarrow d \). Hãy phân tích vectơ \(\overrightarrow {MG} \) theo \(\overrightarrow b ,\,\,\overrightarrow c ,\,\,\overrightarrow d \).
A.\(- \dfrac{1}{6}\left( {\overrightarrow b - 2\overrightarrow c - 2\overrightarrow d } \right)\)
B.\(\dfrac{1}{3}\left( {\overrightarrow a + 2\overrightarrow b - \dfrac{5}{6}\overrightarrow c } \right)\)
C.\(\dfrac{1}{2}\left( { - \overrightarrow a + \dfrac{4}{3}\overrightarrow b - \dfrac{1}{6}\overrightarrow c } \right)\)
D.\(\dfrac{1}{3}\overrightarrow a - \dfrac{1}{6}\overrightarrow b - \dfrac{5}{6}\overrightarrow c \)
A.\(- \dfrac{1}{6}\left( {\overrightarrow b - 2\overrightarrow c - 2\overrightarrow d } \right)\)
B.\(\dfrac{1}{3}\left( {\overrightarrow a + 2\overrightarrow b - \dfrac{5}{6}\overrightarrow c } \right)\)
C.\(\dfrac{1}{2}\left( { - \overrightarrow a + \dfrac{4}{3}\overrightarrow b - \dfrac{1}{6}\overrightarrow c } \right)\)
D.\(\dfrac{1}{3}\overrightarrow a - \dfrac{1}{6}\overrightarrow b - \dfrac{5}{6}\overrightarrow c \)
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Hóa Học lớp 12
