3Fe + 2O2 ==nhiêt độ==> Fe3O4
0,1..........1/15......................................1/30
nFe= 5,6/56= 0,1 (mol)
nFe3O4= (1/3)nFe= (1/3)x0,1= 1/30 (mol)
==> mFe3O4= (1/30)x232= 7,73 (g)
nO2= (2/3)nFe= (2/3)x0,1= 1/15 (mol)
==> VO2= (1/15)x22,4= 1,493 (l)