Tính \(\dfrac{5}{{{x^2} - 6x + 9}}:\dfrac{3}{{{x^2} - 3x}}\)
A.\(\dfrac{{3\left( {x - 3} \right)}}{{5x}}\)
B.\(\dfrac{5}{{3x{{\left( {x - 3} \right)}^2}}}\)
C.\(\dfrac{{15}}{{x{{\left( {x - 3} \right)}^3}}}\)
D.\(\dfrac{{5x}}{{3\left( {x - 3} \right)}}\)
A.\(\dfrac{{3\left( {x - 3} \right)}}{{5x}}\)
B.\(\dfrac{5}{{3x{{\left( {x - 3} \right)}^2}}}\)
C.\(\dfrac{{15}}{{x{{\left( {x - 3} \right)}^3}}}\)
D.\(\dfrac{{5x}}{{3\left( {x - 3} \right)}}\)
Loga
Hóa Học lớp 12
