a) Ta có :
\(x^{10}=1^x\)
Mà \(1^x=1\)
\(\Leftrightarrow x^{10}=1\)
\(\Leftrightarrow x^{10}=1^{10}\)
\(\Leftrightarrow x=1\left(tm\right)\)
Vậy =.
b) \(2^x-15=17\)
\(\Leftrightarrow2^x=17+15\)
\(\Leftrightarrow2^x=32\)
\(\Leftrightarrow2^x=2^5\)
\(\Leftrightarrow x=5\left(tm\right)\)
Vậy =-...
