A.\(x \in \left\{ {0;\,\,3} \right\}\)B.\(x \in \left\{ {0;\,\, - 3} \right\}\)C.\(x \in \left\{ {0;\,\,\dfrac{1}{3}} \right\}\)D.\(x \in \left\{ {0;\,\,1} \right\}\)
A.\(x \in \left\{ { - 3;\,\,3} \right\}\)B.\(x \in \left\{ { - 9;\,\,0;\,\,9} \right\}\)C.\(x \in \left\{ {0;\,\,9} \right\}\)D.\(x \in \left\{ { - 3;\,\,0;\,\,3} \right\}\)
A.\(x \in \left\{ { - 1;\,\,1;\, - 4} \right\}\)B.\(x \in \left\{ { - 1;\,\,1;\,4} \right\}\)C.\(x \in \left\{ {1;\,\,2;\, - 2} \right\}\)D.\(x \in \left\{ { - 1;\,\,2;\, - 2} \right\}\)
A.\(\left( {5x + 2} \right)\left( {5 - 2x} \right)\)B.\(\left( {5x - 2} \right)\left( {5 + 2x} \right)\)C.\(\left( {5x - 2} \right)\left( {5 - 2x} \right)\)D.\(\left( {5x + 2} \right)\left( {5 + 2x} \right)\)
A.\(\left( {x + 5y} \right)\left( {3x - 2y} \right)\)B.\(\left( {x - 5y} \right)\left( {3x + 2y} \right)\)C.\(\left( {x - 5y} \right)\left( {3x - 2y} \right)\)D.\(\left( {x + 5y} \right)\left( {3x + 2y} \right)\)
A.\(y\left( {2x + y} \right)\)B.\(x\left( {2y + x} \right)\)C.\(y\left( {y + 2x} \right)\)D.\(x\left( {y + 2x} \right)\)
A.\({x^2} - 4 = \left( {4 - x} \right)\left( {4 + x} \right)\)B.\({x^2} - 4 = \left( {2 - x} \right)\left( {2 + x} \right)\)C.\({x^2} - 4 = \left( {x - 2} \right)\left( {x + 2} \right)\)D.\({x^2} - 4 = \left( {x - 4} \right)\left( {x + 4} \right)\)
A.\({\left( {x - 1} \right)^3} + 2{\left( {x - 1} \right)^2} = {\left( {x - 1} \right)^2}\left( {x + 1} \right)\)B.\({\left( {x - 1} \right)^3} + 2{\left( {x - 1} \right)^2} = \left( {x - 1} \right)\left[ {{{\left( {x - 1} \right)}^2} + 2\left( {x - 1} \right)} \right]\)C.\({\left( {x - 1} \right)^3} + 2{\left( {x - 1} \right)^2} = \left( {x - 1} \right)\left[ {{{\left( {x - 1} \right)}^2} + 2x - 2} \right]\)D.\({\left( {x - 1} \right)^3} + 2{\left( {x - 1} \right)^2} = \left( {x - 1} \right)\left( {x + 3} \right)\)
A.\(2b\)B.\(a\)C.\(0\)D.\(b\)
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