Ta có : $D=\frac{1}{2} + \frac{1}{2^2} + \frac{1}{2^3} +...+\frac{1}{2^{10}} $
$⇒2D = 1+\frac{1}{2} + \frac{1}{2^2} + ...+ \frac{1}{2^9} $
$⇒2D-D=(1+\frac{1}{2} +\frac{1}{2^2} + \frac{1}{2^9})-(\frac{1}{2} +\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{10}} $
$⇒D=1-\frac{1}{2^{10}} $
Chúc bạn học tốt !