\(VT=\left(3+\sqrt{5}\right)\left(\sqrt{5}-1\right)\sqrt{3-\sqrt{5}}=\dfrac{\left(3+\sqrt{5}\right)\left(\sqrt{5}-1\right)\sqrt{5-2\sqrt{5}+1}}{\sqrt{2}}=\dfrac{\left(3+\sqrt{5}\right)\left(\sqrt{5}-1\right)^2}{\sqrt{2}}=\dfrac{2\left(3+\sqrt{5}\right)\left(3-\sqrt{5}\right)}{\sqrt{2}}=\sqrt{2}.\left(9-5\right)=4\sqrt{2}=VP\)Vậy , đẳng thức được chứng minh.