\(x-\left(\dfrac{1}{4}+\dfrac{1}{3}\right)=-\dfrac{7}{10}\)
\(\Leftrightarrow x-\left(\dfrac{3}{12}+\dfrac{4}{12}\right)=-\dfrac{7}{10}\)
\(\Leftrightarrow x-\dfrac{7}{12}=-\dfrac{7}{10}\)
\(\Leftrightarrow x=\dfrac{7}{12}-\dfrac{7}{10}\)
\(\Leftrightarrow x=\dfrac{35}{60}-\dfrac{42}{60}\)
\(\Leftrightarrow x=-\dfrac{7}{60}\)
Vậy \(x=-\dfrac{7}{60}\)
