Trong không gian Oxyz cho đường thẳng ddx + 11 = dy1 =
A.\(\dfrac{{x + 1}}{4} = \dfrac{y}{5} = \dfrac{{z - 1}}{{13}}\)
B.\(\dfrac{{x + 1}}{3} = \dfrac{y}{{ - 5}} = \dfrac{{z - 1}}{1}\)
C.\(\dfrac{{x - 1}}{3} = \dfrac{y}{{ - 5}} = \dfrac{{z + 1}}{1}\)
D.\(\dfrac{{x - 1}}{4} = \dfrac{y}{5} = \dfrac{{z + 1}}{{13}}\)
A.\(\dfrac{{x + 1}}{4} = \dfrac{y}{5} = \dfrac{{z - 1}}{{13}}\)
B.\(\dfrac{{x + 1}}{3} = \dfrac{y}{{ - 5}} = \dfrac{{z - 1}}{1}\)
C.\(\dfrac{{x - 1}}{3} = \dfrac{y}{{ - 5}} = \dfrac{{z + 1}}{1}\)
D.\(\dfrac{{x - 1}}{4} = \dfrac{y}{5} = \dfrac{{z + 1}}{{13}}\)
Loga
Hóa Học lớp 12
