Sửa đề: Chứng minh: \(4\left(a-b\right)\left(b-c\right)=4\left(b-c\right)^2\)
 Đặt \(\dfrac{a}{2017}=\dfrac{b}{2018}=\dfrac{b}{2019}=k\)
 \(\Rightarrow\left\{{}\begin{matrix}a=2017k\\b=2018k\\c=2019k\end{matrix}\right.\)
 VT: \(4\left(a-b\right)\left(b-c\right)=4\left(2017k-2018k\right)\left(2018k-2019k\right)\)
  \(=4.\left(-k\right).\left(-k\right)=4k^2\) (1)
 VP: \(4\left(b-c\right)^2=4\left(2018k-2019k\right)^2=4k^2\) (2)
 Từ (1) và (2), suy ra:
 \(4\left(a-b\right)\left(b-c\right)=4\left(b-c\right)^2\)\(\Rightarrow\) (đpcm)
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