a, 3x.(25x+15) - 35.(5x+3) = 0
⇔ 15x.(5x+3) - 35.(5x+3) = 0
⇔ (5x+3).(15x-35) =0
⇔ 5x+3=0 ⇔ x = -3/5
15x-35=0 ⇔ x = 7/3
Vậy x ∈ { -3/5 ; 7/3 }
b, (2-3x)(x+11) = (3x-2)(2-5x)
⇔ (2-3x)(x+11) - (3x-2)(2-5x) = 0
⇔ (2-3x)(x+11) + (2-3x)(2-5x) = 0
⇔ (2-3x)( x+11+2-5x) = 0
⇔ (2-3x)(-4x+13) = 0
⇔ 2-3x = 0 ⇔ x= 2/3
-4x+13 = 0 ⇔ x= 13/4
Vậy x ∈ { 2/3 ; 13/4 }