(x-1)(5x+3)=(3x-8)(x-1)
⇒(x-1)(5x+3)-(3x-8)(x-1)=0
⇒(x-1)(5x+3-3x+8)=0
⇒(x-1)(2x+11)=0
⇒\(\left[ \begin{array}{l}x=1\\x=\frac{-11}{2}\end{array} \right.\)
b,(2-3x)(x+11)=(3x-2)(2-5x)
⇒(2-3x)(x+11)-(3x-2)(2-5x)=0
⇒(2-3x)(x+11)+(2-3x)(2-5x)=0
⇒(2-3x)(x+11+2-5x)=0
⇒(2-3x)(13-4x)=0
⇒\(\left[ \begin{array}{l}x=\frac{2}{3}\\x=\frac{13}{4}\end{array} \right.\)
Chúc bạn học tốt nhé! ^^