Đáp án đúng: A
X: H2N-R-COOH (a mol)
$\left| \begin{array}{l}\xrightarrow{+HCl}\,Cl{{H}_{3}}N-R-CO\text{OH}\\\xrightarrow{+NaOH}\,{{H}_{2}}N-R-CO\text{ONa}\end{array} \right.\,$
$\Rightarrow \,\left\{ \begin{array}{l}{{m}_{Cl{{H}_{3}}N-R-CO\text{OH}}}=a.R\,+\,97,5\,=\,10,04\\{{m}_{{{H}_{2}}N-R-CO\text{ONa}}}\,=\,a.R\,+\,83\,=\,8,88\end{array} \right.$
$\Rightarrow \,\left\{ \begin{array}{l}aR\,=\,2,24\\a\,=\,0,08\end{array} \right.\,$$\Rightarrow \,\left\{ \begin{array}{l}a\,=\,0,08\\R\,=\,28\,({{C}_{2}}{{H}_{4}})\end{array} \right.$$\Rightarrow \,{{H}_{2}}N-{{C}_{2}}{{H}_{4}}-COOH$