Chúc bạn học tốt !!
ĐKXĐ : x $\neq$ 1 , x $\neq$ 3
Pt tương đương :
$\frac{(x+5)(x-3)-(x+1)(x-1)-8}{(x-1)(x-3)}$ = 0 = 0
⇔ x²+2x-15-x²+1-8 =0
⇔ 2x = 22
⇔ x=11 ( thỏa mãn )
Vậy : pt có nghiệm là x=11.
Đáp án:
Pt vô nghiệm
Giải thích các bước giải:
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