bài 1: giả pt
a, $x^{2}$ -x - 2$\sqrt[]{1+16x}$=2
b, x(2x-2$\sqrt[]{x^{2}-9}$ ) + y(3y-2$\sqrt[]{2y^{2}-4}$ ) = 12
c, $\frac{36}{\sqrt[]{x-2}}$ + $\frac{4}{\sqrt[]{y-2}}$ = 28 - 4$\sqrt[]{x-2}$ -$\sqrt[]{y-1}$
d, $x^{2}$ - 5x +36= 8$\sqrt[]{3x+2}$
e, $x^{2}$ +5x +1= (x+3)$\sqrt[]{x^{2}+4}$